Вопрос задан 09.07.2023 в 13:06. Предмет Алгебра. Спрашивает Гаркавенко Алексей.

Реши систему уравнений, используя способ сложения. (Сначала записывай наименьшие значения.)

{xa+x=6xa+a=4 {x1= a1= {x2= a2= Смотреть ответ slanovtimur06 slanovtimur06 Ответ: {x1=−2a1=−4 {x2=3a2=1 Объяснение: Новые вопросы в Алгебра СРОЧНО!!! Докажите, что при любом целом значении х значение выражения делится на 10. (3x-1)(3x+1)+(x-4)^2-2x+5 ПОМОГИТЕ ПОЖАЛУЙСТА С АЛГЕБРОЙ, СРОЧНО Какие из представленных значений С и М соответствует уравнению C(X+M)=0, если X=-7. С и М - больше нуля: Выберите один ответ: OLM=7C=2 2. М=3 C=0 ф 0 … 3. M=0 c=0 в​ Необходимо решить уравнение: 2*(x+2х+3х+4x)=600 Выберите один ответ: 0 1. 20 0 2. 30 0 3. 4​ сколькими способами можно разложить 7 монет в 3 кармана? Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Для начала решим систему уравнений методом сложения:

Система уравнений:

  1. xa + x = 6
  2. xa + a = 4

Сначала выразим x из первого уравнения: xa + x = 6 x(a + 1) = 6 x = 6 / (a + 1)

Теперь подставим выражение для x во второе уравнение: xa + a = 4 (6 / (a + 1))a + a = 4 6a / (a + 1) + a = 4

Приведём дробь к общему знаменателю: 6a + a(a + 1) = 4(a + 1) 6a + a^2 + a = 4a + 4

Упростим уравнение: a^2 + 3a - 4 = 0

Факторизуем квадратное уравнение: (a + 4)(a - 1) = 0

Получаем два возможных значения для 'a': a = -4 или a = 1

Теперь подставим найденные значения 'a' обратно в первое уравнение, чтобы найти соответствующие 'x':

  1. При a = -4: x = 6 / (-4 + 1) = -2 x1 = -2, a1 = -4

  2. При a = 1: x = 6 / (1 + 1) = 3 x2 = 3, a2 = 1

Итак, решение системы уравнений: x1 = -2, a1 = -4 x2 = 3, a2 = 1

Теперь перейдем к следующему вопросу:

Докажем, что при любом целом значении 'x' значение выражения (3x - 1)(3x + 1) + (x - 4)^2 - 2x + 5 делится на 10.

Раскроем скобки и упростим выражение: (3x - 1)(3x + 1) + (x - 4)^2 - 2x + 5 = 9x^2 - 1 + x^2 - 8x + 16 - 2x + 5 = 10x^2 - 10x + 20

Выражение 10x^2 - 10x + 20 делится на 10 без остатка для любого целого значения 'x', так как каждый член этого выражения делится на 10. Таким образом, утверждение верно.

Следующий вопрос:

Для уравнения C(X + M) = 0, если X = -7 и C > 0, M > 0, то значение C должно быть равно 2, так как C * (X + M) = 2 * (-7 + M) = 2M - 14. Если M > 0, то 2M - 14 не будет равно нулю, за исключением случая, когда M = 7, тогда 2 * 7 - 14 = 0.

Наконец, решим уравнение:

2 * (x + 2x + 3x + 4x) = 600 2 * 10x = 600 20x = 600 x = 600 / 20 x = 30

Итак, решение уравнения: x = 30.

Ответ на последний вопрос о разложении монет в карманы: Существует несколько способов рассадить 7 монет в 3 кармана. Например:

  • 3 монеты в первом кармане, 3 монеты во втором и 1 монета в третьем.
  • 2 монеты в первом кармане, 2 монеты во втором и 3 монеты в третьем.

И так далее. Общее количество способов можно подсчитать, используя комбинаторику.

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