Question

(x²-x-56):(13x+91)=0​

Answer 1

Ответ:

Снизу закрепила фото

Объяснение:

Answer 2

Ответ:

Во вложении прикрепил решение

Объяснение:

Answer 3

To solve the equation $\frac{x^2 - x - 56}{13x + 91} = 0$, you need to find the values of $x$ that make the expression equal to zero.

First, factor the numerator and denominator:

$x^2 - x - 56 = (x - 8)(x + 7)$ $13x + 91 = 13(x + 7)$

Now the equation becomes:

$\frac{(x - 8)(x + 7)}{13(x + 7)} = 0$

Notice that the term $x + 7$ appears in both the numerator and denominator. This means that the fraction will be equal to zero when the numerator $(x - 8)(x + 7)$ is equal to zero, since a zero in the denominator would make the whole fraction undefined.

So, set each factor equal to zero:

$x - 8 = 0$ → $x = 8$ $x + 7 = 0$ → $x = -7$

These are the two solutions for $x$ that make the fraction $\frac{x^2 - x - 56}{13x + 91} = 0$.

Therefore, the solutions are $x = 8$ and $x = -7$.