Question

1) x– 5y = 8, 3) 5a– 3b= 14, 2x+ 4y = 30; 2a + b = 10; 2) 2x– y= 1, 4) 2x– 3y = 2, 7x – 6y= –4; 4x – 5y = 1

Answer 1

1)х-5у=8

х=8+5у

х=8+5у

2)2х-у=1

2х+=1+у

х=1/2+у/2

х=1+у/2

3)5а-3д=14

5а=14+3д

а=14/5+3/5д

2х+4у=30

2х=30-4у

х=15-2у

2а+д=10

2а=10-д

а=5-д/2

4)2х-3у=2

2х=2+3у

х=1+3/2у

7х-6у= -4

7х= -4+6у

7х=4/7+6/7у

4х-5у=1

4х=1+5у

х=1/4+5/4у

Answer 2

It seems like you've provided a system of linear equations:

1. x - 5y = 8
2. 2x + 4y = 30
3. 5a - 3b = 14
4. 2a + b = 10
5. 2x - y = 1
6. 2x - 3y = 2
7. 7x - 6y = -4
8. 4x - 5y = 1

If you're looking to solve this system of equations, you can use various methods such as substitution, elimination, or matrices. Let's solve it using the substitution method:

Let's start with equations 1) and 2):

1. x - 5y = 8
2. 2x + 4y = 30

From equation 1), we can express x in terms of y: x = 8 + 5y.

Substitute this value of x into equation 2):

2(8 + 5y) + 4y = 30 16 + 10y + 4y = 30 14y = 14 y = 1

Now that we have the value of y, we can substitute it back into the equation x = 8 + 5y:

x = 8 + 5(1) x = 13

So, the solution for the first set of equations is x = 13 and y = 1.

You can follow a similar process to solve the remaining sets of equations. If you have any specific equations you'd like me to solve, or if you have any other questions, feel free to ask!