Question

2sin(п/6-L)+cos(п+L)+корінь3sinL​

Answer 1

Объяснение:

відбулося спрощення виразу

Answer 2

To simplify the given expression, let's break it down step by step:

1. Start with the expression: 2sin(π/6 - L) + cos(π + L) + √3sin(L).

2. Recall the trigonometric identities:

   • sin(π/6 - L) = sin(π/6)cos(L) - cos(π/6)sin(L) = (1/2)cos(L) - (√3/2)sin(L)
   • cos(π + L) = cos(π)cos(L) - sin(π)sin(L) = -cos(L)
   • sin(L) can remain as it is.

3. Substitute the values back into the expression: 2((1/2)cos(L) - (√3/2)sin(L)) + (-cos(L)) + √3sin(L)

4. Simplify the expression: cos(L) - √3sin(L) - cos(L) + √3sin(L) + √3sin(L) = √3sin(L)

Therefore, the simplified form of the expression 2sin(π/6 - L) + cos(π + L) + √3sin(L) is √3sin(L).