Question

Разложить на множители 1)14x+21у 2)6x^2-4x^3+10x^4 3)8a^46^3-12a^2b^4+16a^3b^2 3)8m(a-3)+n(3-a) 4)(a-b)^2-3(b-a) 5)-(x+2y)-4(x-2y)^2 6)3a(2x-7)+5b(7-2x)

Answer 1

Ответ:

1)14x+21у =7(2х+3у)

2)6x^2-4x^3+10x^4=2х² (3-2х+5х²)

3)8a^46^3-12a^2b^4+16a^3b^2=4а²b²(2a²b-3b²+4a)

3)8m(a-3)+n(3-a)=(3-a)(-8m+n)

4)(a-b)^2-3(b-a) =(a-b)(a-b+3)

5)-(x+2y)-4(x-2y)^2 =(х-2у)(1+4(х-2у))

6)3a(2x-7)+5b(7-2x)=(2х-7)(3а-5b)

Объяснение:

Answer 2

1. 14x + 21y Taking out the common factor of 7, we have: 7(2x + 3y)

2. 6x^2 - 4x^3 + 10x^4 Factoring out the common factor of 2x^2, we get: 2x^2(3 - 2x + 5x^2)

3. 8a^4b^3 - 12a^2b^4 + 16a^3b^2 Factoring out the common factor of 4a^2b^2, we have: 4a^2b^2(2a^2b - 3b^3 + 4a^2)

4. 8m(a - 3) + n(3 - a) Rearranging the terms inside the parentheses, we get: 8m(-3 + a) + n(3 - a) Factoring out -1 from the second set of parentheses, we have: 8m(-3 + a) - n(a - 3) Rearranging the terms, we get: 8m(a - 3) - n(a - 3) Factoring out the common factor of (a - 3), we get: (a - 3)(8m - n)

5. -(x + 2y) - 4(x - 2y)^2 Expanding the square, we have: -(x + 2y) - 4(x^2 - 4xy + 4y^2) Distributing the negative sign, we get: -x - 2y - 4x^2 + 16xy - 16y^2

6. 3a(2x - 7) + 5b(7 - 2x) Rearranging the terms inside the parentheses, we get: 3a(-7 + 2x) + 5b(7 - 2x) Factoring out -1 from the first set of parentheses, we have: 3a(2x - 7) - 5b(2x - 7) Factoring out the common factor of (2x - 7), we get: (2x - 7)(3a - 5b)