Question

2x - 2y -10 = 0 2x -8 = 0

Answer 1

Ответ:

(4; -1)

Объяснение:

$\left\{ \begin{array}{ll}2x-2y-10=0\\2x-8=0\end{array}$

$\left\{ \begin{array}{ll}2x-2y-10=0\\2x=8\end{array}$

$\left\{ \begin{array}{ll}2x-2y-10=0\\x=4\end{array}$

$\left\{ \begin{array}{ll}2\cdot 4-2y-10=0\\x=4\end{array}$

$\left\{ \begin{array}{ll}8-2y-10=0\\x=4\end{array}$

$\left\{ \begin{array}{ll}-2y=2\\x=4\end{array}$

$\left\{ \begin{array}{ll}y=-1\\x=4\end{array}$

Answer 2

To solve the given system of equations:

Equation 1: 2x - 2y - 10 = 0 Equation 2: 2x - 8 = 0

We can start by isolating one variable in either equation and substituting it into the other equation.

From Equation 2, we have 2x - 8 = 0. Solving for x, we get: 2x = 8 x = 8/2 x = 4

Now, substitute the value of x into Equation 1: 2(4) - 2y - 10 = 0 8 - 2y - 10 = 0 -2y - 2 = 0 -2y = 2 y = 2/(-2) y = -1

Therefore, the solution to the system of equations is x = 4 and y = -1.