Question

1)(1-a) (1+a+a²)+a³​

Answer 1

Ответ:

Ответ: 1

Объяснение:

Answer 2

Ответ:

(1-а)(1+а+а²)+а³=1-а³+а³=1

Answer 3

It seems like you're looking for the expansion of the expression $(1-a) (1+a+a^2)+a^3$. Let's break it down step by step:

1. Expand $(1-a) \cdot (1+a+a^2)$: $(1-a) \cdot (1+a+a^2) = 1 \cdot (1+a+a^2) - a \cdot (1+a+a^2)$ $= 1 + a + a^2 - a - a^2 - a^3$ $= 1 - a^3$

2. Add $a^3$: $(1 - a^3) + a^3 = 1$

So, the expression $(1-a) (1+a+a^2)+a^3$ simplifies to $1$.