Question

25х 2 + 60х + 36 = 0

Answer 1

Ответ:

x1 = -1,2

Объяснение:

$25x^{2}+60x+36=0\\25x^{2}+60x+36=0\\ D=b^2-4ac\\D=60^2-4*25*36\\D=3600-3600\\D=0\\\\\sqrt{D}=\sqrt{0}=0\\ x_{1}=\frac{-b+\sqrt{D}}{2a}=\frac{-60+0}{50}=\frac{-60}{50\frac{-6}{5}}=-1,2$

Так как дискриминант равен 0, то уравнение имеет всего 1 корень

Answer 2

The equation you've provided is a quadratic equation, which is in the form of $ax^2 + bx + c = 0$, where $a$, $b$, and $c$ are constants. In your case, the equation is:

$25x^2 + 60x + 36 = 0$

To solve this quadratic equation, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your equation, $a = 25$, $b = 60$, and $c = 36$. Plugging these values into the formula, you get:

$x = \frac{-60 \pm \sqrt{60^2 - 4 \cdot 25 \cdot 36}}{2 \cdot 25}$

Simplify the expression under the square root:

$x = \frac{-60 \pm \sqrt{3600 - 3600}}{50}$

Since both terms inside the square root cancel out, you get:

$x = \frac{-60 \pm \sqrt{0}}{50}$

Any square root of zero is zero, so:

$x = \frac{-60 \pm 0}{50}$

This results in two identical solutions:

$x = \frac{-60}{50} = -1.2$

So, the solution to the equation $25x^2 + 60x + 36 = 0$ is $x = -1.2$.