Вопрос задан 06.07.2023 в 14:06. Предмет Алгебра. Спрашивает Васильев Данил.

Составь словесную модель по математической: {y−x=375xy=34 Число учащихся одной школы относится к

числу учащихся другой школы как : . Сколько учащихся в каждой из этих школ, если число учащихся второй школы 375 числа учащихся первой школы? Смотреть ответ arina968 arina968 0 <!--c--> Составлена система двух уравнений с двумя переменными: {y−x=475xy=34 Пусть x — число учащихся первой школы, а y — число учащихся второй школы. Из второго уравнения xy=34 делаем вывод, что число учащихся первой школы относится к числу учащихся второй школы, как 3:4. Из второго уравнения y−x=475 делаем вывод, что число учащихся второй школы на 475 больше числа учащихся первой школы. Новые вопросы в Алгебра Даю 100 балов 7*х+7=49​ (x+2)²+(x-3y)²=0 срочно даю дофига ​ Помогите пожалуйста X^2-10x+16&gt;=0 6. Відомо, що а+b=5, ab=-2. Знайдіть значення виразу (a-b)в квадраті​ Знайти f(27), якщо f(x) = √3х​a) 9 b)-9 в) 4 г)6 Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Давайте разберёмся с данной задачей.

У нас есть две школы: первая и вторая. Пусть x обозначает число учащихся в первой школе, а y - число учащихся во второй школе.

Из условия задачи у нас есть два уравнения:

  1. y - x = 375
  2. y = 3/4 * x (число учащихся первой школы относится ко второй как 3:4)

Также дано, что число учащихся во второй школе y равно 375 раз числу учащихся в первой школе x.

Из второго уравнения мы можем выразить y через x: y = 3/4 * x

Теперь мы можем подставить это значение y в первое уравнение: 3/4 * x - x = 375

Решим это уравнение относительно x: -1/4 * x = 375 x = -375 * -4 = 1500

Теперь, зная значение x, мы можем найти y через второе уравнение: y = 3/4 * x = 3/4 * 1500 = 1125

Итак, в первой школе 1500 учащихся, а во второй - 1125 учащихся.

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