Question

(Y-4)(2Y+3)-(y-2)^2=?

Answer 1

Ответ:

$2y^{2} -y^{2} -5y + 4y-16= y^{2} -y -16$

Answer 2

Let's simplify the given expression step by step:

1. Expand the first term: (Y-4)(2Y+3) = Y * 2Y + Y * 3 - 4 * 2Y - 4 * 3 = 2Y^2 + 3Y - 8Y - 12 = 2Y^2 - 5Y - 12

2. Expand the second term: (Y-2)^2 = Y^2 - 2 * Y * 2 + 2^2 = Y^2 - 4Y + 4

Now, substitute the expanded terms back into the original expression:

(2Y^2 - 5Y - 12) - (Y^2 - 4Y + 4)

Distribute the negative sign to each term inside the parentheses:

2Y^2 - 5Y - 12 - Y^2 + 4Y - 4

Combine like terms:

2Y^2 - Y^2 - 5Y + 4Y - 12 - 4

Simplify further:

Y^2 - Y - 16

So, the simplified expression is Y^2 - Y - 16.