Question

4(x-4)-1<7(x+3)+1.....​

Answer 1

Ответ:

x ∈ (-13; +∞)

Объяснение:

4(x-4)-1 < 7(x+3)+1

4x-16-1 < 7x+21+1

4x-7x < 22+17

-3x < 39

x > -13

Answer 2

To solve the inequality $4(x-4)-1 < 7(x+3)+1$, follow these steps:

Step 1: Distribute the coefficients on both sides of the inequality. $4x - 16 - 1 < 7x + 21 + 1$

Simplify: $4x - 17 < 7x + 22$

Step 2: Move the $7x$ term to the left side by subtracting $7x$ from both sides of the inequality. $4x - 7x - 17 < 22$

Simplify: $-3x - 17 < 22$

Step 3: Move the constant term (-17) to the right side by adding 17 to both sides of the inequality. $-3x < 39$

Step 4: Divide both sides of the inequality by -3. Since you're dividing by a negative number, the inequality direction will flip. $x > -13$

So, the solution to the inequality $4(x-4)-1 < 7(x+3)+1$ is $x > -13$.