Question

Sina+sin2a/1+cosa+cos2a

Answer 1

Ответ:

Sina+sin2a+cosa+cos2a

Объяснение:

любое выражение, разделенное на 1, равно самому себе.

поэтому просто убираешь 1 и получаешь ответ.

Answer 2

The expression you've provided seems to be a trigonometric expression. Let's simplify it step by step:

Expression: (sin(a) + sin(2a)) / (1 + cos(a) + cos(2a))

First, let's try to simplify the numerator and denominator separately:

Numerator: sin(a) + sin(2a)

Using the trigonometric identity: sin(2a) = 2 * sin(a) * cos(a)

Numerator: sin(a) + 2 * sin(a) * cos(a) = sin(a) * (1 + 2 * cos(a))

Denominator: 1 + cos(a) + cos(2a)

Using the trigonometric identity: cos(2a) = 2 * cos^2(a) - 1

Denominator: 1 + cos(a) + 2 * cos^2(a) - 1 = cos(a) + 2 * cos^2(a)

Now, substitute the simplified numerator and denominator back into the original expression:

(sin(a) * (1 + 2 * cos(a))) / (cos(a) + 2 * cos^2(a))

Now, if you factor out a cos(a) from the denominator:

(sin(a) * (1 + 2 * cos(a))) / (cos(a) * (1 + 2 * cos(a)))

The cos(a) terms in the numerator and denominator cancel out:

sin(a) / 1 = sin(a)

So, the simplified expression is just sin(a).