Question

(x-2) * (x-3) - (x-1)* (x-4)=0

Answer 1

(x-2)(x-3)-(x-1)(x-4)=0

x²-2x-3x+6-x²+x+4x-4=0

2=0

Не имеет решения

Answer 2

It seems like you have a quadratic equation there. Let's solve it step by step:

Given equation:

$(x - 2) \cdot (x - 3) - (x - 1) \cdot (x - 4) = 0$

Let's expand the terms:

$x^2 - 3x - 2x + 6 - (x^2 - 4x - x + 4) = 0$

Now simplify:

$x^2 - 5x + 6 - x^2 + 5x - 4 = 0$

Now the $x^2$ terms cancel out, as well as the $5x$ terms:

$6 - 4 = 0$

$2 = 0$

Since $2$ cannot equal $0$, the equation is not true for any value of $x$. This means there is no solution that satisfies the given equation. The equation has no real solutions.