Question

(х-3)²-(х+1)²=12 (3х-2)²+1(1-3х)(3х+2)=36х(х-2)(х-3)=8+х(х-2,5)²(6х-1)²-(5х+2)(6х+5)=6+(х-1)²-37х(2х-1)(2х+1)=2(х-3)²+х(2х-3)​

Answer 1

Ответ:решение первых 3

Объяснение:

Answer 2

It looks like you've provided a system of equations. Let's go step by step to solve this system:

1. (х-3)² - (х+1)² = 12

Expand both sides of the equation: x² - 6x + 9 - (x² + 2x + 1) = 12 x² - 6x + 9 - x² - 2x - 1 = 12 -8x + 8 = 12

Subtract 8 from both sides: -8x = 4

Divide both sides by -8: x = -0.5

2. (3х-2)² + 1(1-3х)(3х+2) = 36

Expand and simplify: 9x² - 12x + 4 + (3x - 1)(3x + 2) = 36 9x² - 12x + 4 + 9x² + 6x - 2 = 36 18x² - 6x + 2 = 36

Subtract 2 from both sides: 18x² - 6x = 34

Divide both sides by 2: 9x² - 3x = 17

3. (х-2)(х-3)(х) = 8

Expand the left side: x³ - 5x² + 6x - 8 = 0

4. (х-2.5)²(6х-1)² - (5х+2)(6х+5) = 6 + (х-1)²

Expand and simplify: (x² - 5x + 6.25)(36x² - 12x + 1) - (30x² + 17x + 10) = 6 + x² - 2x + 1 36x⁴ - 222x³ + 375.25x² - 112x + 6.25 - 30x² - 17x - 10 = 7 + x² - 2x 36x⁴ - 222x³ + 345.25x² - 129x - 3 = x² - 2x + 7

Move all terms to one side: 36x⁴ - 222x³ + 344.25x² - 127x - 10 = 0

5. 37х(2х-1)(2х+1) = 2(х-3)² + х(2х-3)

Expand and simplify: 37x(4x² - 1) = 2x² - 12x + 2x² - 3x 148x³ - 37x = 4x² - 15x

Move all terms to one side: 148x³ - 4x² - 22x = 0

Now you have a system of equations and polynomial equations. Solving these equations simultaneously is a complex process and may require numerical methods or advanced algebraic techniques. If you're looking for specific numerical solutions, you might consider using a computer algebra system or a numerical solver.