Question

(z + 12)2 – Z2 = 44пжж​

Answer 1

Ответ:

Раскрываем скобки: 2z+24-z^2-44=0;

Получаем квадратное уравнение

-z²+2z-20=0;  [* -1]

z²-2z+20=0;

Дискриминант <0 - нет корней

Объяснение:

Answer 2

It looks like you've provided an equation involving the variable "z". The equation you've written is:

$(z + 12)^2 - z^2 = 44\pi$.

Let's solve this equation step by step:

Expand the left side of the equation: $z^2 + 24z + 144 - z^2 = 44\pi$.

The $z^2$ terms cancel out: $24z + 144 = 44\pi$.

Subtract 144 from both sides: $24z = 44\pi - 144$.

Divide both sides by 24: $z = \frac{44\pi - 144}{24}$.

Now, you have an expression for the value of $z$ in terms of $pi$.

However, I noticed a small error in the original equation you provided. The symbol "пжж" seems to be a typo or a placeholder. If you have a specific numerical value for "пжж", please provide it so that I can give you a more precise answer.