Question

7x³-28x=0; 81x³+36x²+4x=0

Answer 1

Ответ:

решение в прикрепленном фото

Answer 2

Ответ:

Вот так

Объяснение:

Answer 3

It looks like you have two cubic equations that you'd like to solve for the variable x:

Equation 1: 7x³ - 28x = 0 Equation 2: 81x³ + 36x² + 4x = 0

Let's solve each equation separately:

Equation 1: 7x³ - 28x = 0

Step 1: Factor out the common term x: x(7x² - 28) = 0

Step 2: Factor the quadratic term: x(7x² - 28) = x(7x² - 4x²)

Step 3: Factor out the common factor, which is x²: x(7x² - 4x²) = x²(7 - 4)

Step 4: Simplify: x²(3) = 3x²

So, the solutions for Equation 1 are x = 0 and x = ±√3.

Equation 2: 81x³ + 36x² + 4x = 0

This equation is a bit more complex, and it might not have simple integer solutions. We can attempt to solve it numerically using methods like numerical root-finding algorithms or calculators.

It's important to note that cubic equations can have complex solutions as well. If you're looking for approximate numerical solutions, you might consider using tools like numerical solvers or software like Python with libraries such as NumPy or SymPy to find the roots.

If you're interested in a specific numerical approximation, please let me know and I can guide you through the process using a numerical solver or other methods.