Question

A + b = -37, с = 0,8. Найдите: 1) a+b+c; 2) a+b-c; 3) 2(a+b)-3c; 4) a-2c+b; 5) 3a+3b+3c.

Answer 1

1) -37+0.8=-36.2

2)-37-0.8=-37.8

3)-37*2-3*0.8=-74-2.4=-76.4

4) -37-2*0.8=-37-1.6=-38.6

5)3*(a+b+c)=3*(-36.2)=-108.6

Answer 2

Давайте решим данную систему уравнений:

1. a + b + c = a + b + 0.8 = -37 + 0.8 = -36.2
2. a + b - c = a + b - 0.8 = -37 - 0.8 = -37.8
3. 2(a + b) - 3c = 2(-37) - 3(0.8) = -74 - 2.4 = -76.4
4. a - 2c + b = a + b - 2c = -37 - 2(0.8) = -37 - 1.6 = -38.6
5. 3a + 3b + 3c = 3(a + b + c) = 3(-36.2) = -108.6

Итак, результаты вычислений:

1. a + b + c = -36.2
2. a + b - c = -37.8
3. 2(a + b) - 3c = -76.4
4. a - 2c + b = -38.6
5. 3a + 3b + 3c = -108.6