Question

X+y=20, 0,5x+y=0 система​

Answer 1

Ответ: у=20-х=-0,5*х или 20=0,5*х или х=40, тогда у=20-40=-20.

Объяснение:

Answer 2

x+y=20,

5x+10y=0, х=-2у подставим в первое уравнение.

-2у+у=20,   у=-20;       х=40

Ответ (40;-20)

Answer 3

To solve the system of equations:

Equation 1: x + y = 20 Equation 2: 0.5x + y = 0

We can use the method of substitution or elimination to find the values of x and y that satisfy both equations. Let's use the elimination method:

Multiply Equation 2 by 2 to eliminate the decimals: 2 * (0.5x + y) = 2 * 0 x + 2y = 0

Now we have the following system of equations:

Equation 1: x + y = 20 Equation 3: x + 2y = 0

To eliminate x, subtract Equation 3 from Equation 1:

(x + y) - (x + 2y) = 20 - 0 x + y - x - 2y = 20 -y = 20

Divide both sides by -1 to solve for y: y = -20

Now substitute the value of y back into Equation 1 to solve for x:

x + (-20) = 20 x - 20 = 20 x = 20 + 20 x = 40

Therefore, the solution to the system of equations is x = 40 and y = -20.