Question

X+7y=58; -x +12y=75 срооооочнооо​

Answer 1

Ответ:

х+7у=58

х+7у-58=58-58

х+7у-58=0

-х+12у=75

-х+12у-75=0

х-12у+75=0

Answer 2

It seems like you have a system of linear equations that you need to solve. The system is as follows:

Equation 1: $x + 7y = 58$ Equation 2: $-x + 12y = 75$

To solve for $x$ and $y$, you can use the method of substitution or elimination. I'll use the elimination method here:

Step 1: Add the two equations to eliminate $x$: Adding Equation 1 and Equation 2 gives: $(x + 7y) + (-x + 12y) = 58 + 75$ $7y + 12y = 133$ $19y = 133$ $y = \frac{133}{19}$ $y = 7$

Step 2: Substitute the value of $y$ back into either Equation 1 or Equation 2 to solve for $x$. Let's use Equation 1: $x + 7 \cdot 7 = 58$ $x + 49 = 58$ $x = 58 - 49$ $x = 9$

So, the solution to the system of equations is: $x = 9$ $y = 7$