Question

(x-4)*(x+2)-(x-5)*(x-6)=3x

Answer 1

$(x-4)(x+2)-(x-5)(x-6)=3x\\\\x^{2} +2x-4x-8-(x^{2} -6x-5x+30)=3x\\\\x^{2} -2x-8-x^{2} +11x-30=3x\\\\9x-3x=38\\\\6x=38\\\\x=6\frac{1}{3}$

Answer 2

Let's solve the given equation step by step:

(x - 4) * (x + 2) - (x - 5) * (x - 6) = 3x

First, expand the expressions within the parentheses:

(x^2 + 2x - 4x - 8) - (x^2 - 6x - 5x + 30) = 3x

Simplify further:

x^2 - 2x - 8 - x^2 + 11x - 30 = 3x

Combine like terms:

-2x + 11x - 2x - 8 - 30 = 3x

7x - 38 = 3x

Now, subtract 3x from both sides of the equation:

7x - 3x - 38 = 3x - 3x

4x - 38 = 0

Add 38 to both sides of the equation:

4x - 38 + 38 = 0 + 38

4x = 38

Finally, divide both sides by 4:

4x / 4 = 38 / 4

x = 9.5

So, the solution to the equation is x = 9.5.