Question

(5/х-7)-(2/х)+(3х+21/49-х)​

Answer 1

0
5/x-7-2/x-3x/x^2-49+21/49-x^2=

=5/x-7-2/x-3/x-49+21/49-x^2=

=5/x-7-5/x-49+21/49-x^2=

=-7-49+21/49-x^2=

=-56+21/49-x^2

Answer 2

To simplify the given expression, let's combine the fractions and perform any necessary operations:

(5/x - 7) - (2/x) + (3x + 21)/(49 - x)

First, let's find a common denominator for the fractions involving 'x':

The common denominator for the fractions 5/x, 2/x, and (3x + 21)/(49 - x) is 'x(49 - x)'.

Now, we'll rewrite each fraction with the common denominator:

(5 * (49 - x))/(x * (49 - x)) - (2 * (49 - x))/(x * (49 - x)) + ((3x + 21) * x)/((49 - x) * x)

Now, we can combine the fractions:

(245 - 5x)/(x * (49 - x)) - (98 - 2x)/(x * (49 - x)) + (3x^2 + 21x)/(x * (49 - x))

Next, we'll combine the numerators:

(245 - 5x - 98 + 2x + 3x^2 + 21x)/(x * (49 - x))

Simplify the numerator:

(3x^2 + 18x + 147)/(x * (49 - x))

Now, the expression is:

(3x^2 + 18x + 147)/(x * (49 - x))

If you want to further simplify this expression, you might need more context about the values of 'x' or if there are any restrictions on its values. If 'x' has a specific value, you can substitute it in to get a numerical result.