Question

A)(2x+5)×(-x+8)=0; б(-3x-10)×(2x+8)=0; в(x-5)×(x+6)×(-x-7)=0​

Answer 1

Ответ:x1=-2,5, x2=8

x1=-4, x2=-10/3

x1=-7, x2=-6, x3=5

Объяснение:

а)2x+5=0

-x+8=0

x=-2,5

x=8

б)-3х-1-=0

2x+8=0

x=-$\frac{10}{3}$

x=-4

в)x-5=0

x+6=0

-x-7=0

x=5

x=-6

x=-7

Answer 2

To solve the given equations, we can use the zero product property, which states that if a product of factors is equal to zero, then at least one of the factors must be zero. We'll apply this property to each equation separately:

A) (2x+5) × (-x+8) = 0

For this equation to be true, either (2x+5) must be zero or (-x+8) must be zero. So we have two cases:

Case 1: 2x+5 = 0 Solving this equation, we subtract 5 from both sides: 2x = -5 Dividing both sides by 2: x = -5/2 or -2.5

Case 2: -x+8 = 0 Adding x to both sides: 8 = x x = 8

So the solutions for equation A) are x = -5/2, x = -2.5, and x = 8.

B) (-3x-10) × (2x+8) = 0

For this equation to be true, either (-3x-10) must be zero or (2x+8) must be zero. So we have two cases:

Case 1: -3x-10 = 0 Adding 10 to both sides: -3x = 10 Dividing both sides by -3 (remember to change the sign when dividing by a negative number): x = -10/3 or -3.33 (approximately)

Case 2: 2x+8 = 0 Subtracting 8 from both sides: 2x = -8 Dividing both sides by 2: x = -4

So the solutions for equation B) are x = -10/3 and x = -4.

C) (x-5) × (x+6) × (-x-7) = 0

For this equation to be true, either (x-5) must be zero, (x+6) must be zero, or (-x-7) must be zero. So we have three cases:

Case 1: x-5 = 0 Adding 5 to both sides: x = 5

Case 2: x+6 = 0 Subtracting 6 from both sides: x = -6

Case 3: -x-7 = 0 Adding 7 to both sides: -x = 7 Multiplying both sides by -1 (remember to change the sign when multiplying by a negative number): x = -7

So the solutions for equation C) are x = 5, x = -6, and x = -7.

In summary: A) x = -5/2, x = -2.5, and x = 8 B) x = -10/3 and x = -4 C) x = 5, x = -6, and x = -7