Question

Cos65cos40+sin65sin40/sin37cos12-cos37sin12

Answer 1

$\frac{Cos65^{0}Cos40^{0}+Sin65^{0}Sin40^{0}}{Sin37^{0}Cos12^{0}-Cos37^{0}Sinx^{2}12^{0}}=\frac{Cos(65^{0}-40^{0})}{Sin(37^{0} -12^{0})} =\frac{Cos25^{0}}{Sin25^{0}}=Ctg25^{0}\\\\Otvet:\boxed{Ctg25^{0}}$

Answer 2

Ответ:

котангенс25

Объяснение:

cos65cos40+sin65sin40/sin37cos12-cos37sin12=cos(65-40)/sin(37-12)=

=cos25/sin25=котангенс25

Answer 3

To simplify the expression cos(65)cos(40) + sin(65)sin(40) / sin(37)cos(12) - cos(37)sin(12), we can use trigonometric identities.

First, let's simplify the numerator: cos(65)cos(40) + sin(65)sin(40)

Using the identity cos(A - B) = cos(A)cos(B) + sin(A)sin(B), we can rewrite the expression as: cos(65 - 40)

This simplifies to cos(25).

Now let's simplify the denominator: sin(37)cos(12) - cos(37)sin(12)

Using the identity sin(A - B) = sin(A)cos(B) - cos(A)sin(B), we can rewrite the expression as: sin(37 - 12)

This simplifies to sin(25).

Now we have: cos(25) / sin(25)

Using the identity tan(A) = sin(A) / cos(A), we can rewrite the expression as: tan(25)

So, the simplified expression is tan(25).