Question

1)2х-|х|=1 2)7|х|-3(х+2) =-10​

Answer 1

Ответ: 1) для х>0 имеем 2*х-х=1⇒х=1. Для х<0 имеем 2*х+х=1⇒х=1/3 - нет решения. В итоге х=1.

2) для х>0 имеем 7*х-3*х-6=-10⇒4*х=-4⇒х=-1 - нет решения. Для х<0 имеем -7*х-3*х-6=-10⇒-10*х=-4⇒х=0,4 - нет решения. В итоге нет решения.

Объяснение:

Answer 2

Ответ:

Объяснение:1)  при х≥0, 2x-x=1; x=1;

                            при х<0, 2x+x=1,  3x=1, x=1/3 --не уд-ет условию х<0.

ответ: 1.    

2)7|x|-3x-6= - 10;   7|x|-3x= -4; 7|x|=3x-4;

7x=3x-4 или 7x= -(3x-4) при условии 3х-4≥0,

х= -1  или   х=0,4 при х≥4/3;

ответ:∅

Answer 3

To solve these equations, we need to isolate the variable "x" in each equation. Let's go through each one step by step:

Equation 1: $2x - |x| = 1$

Here, we have an absolute value equation. To solve it, we'll need to consider two cases: one where $x$ is positive, and another where $x$ is negative.

Case 1: $x$ is positive ($x \geq 0$) In this case, $|x| = x$, so the equation becomes: $2x - x = 1$ $x = 1$

Case 2: $x$ is negative ($x < 0$) In this case, $|x| = -x$, so the equation becomes: $2x - (-x) = 1$ $3x = 1$ $x = \frac{1}{3}$

So, the solutions for Equation 1 are $x = 1$ and $x = \frac{1}{3}$.

Equation 2: $7|x| - 3(x + 2) = -10$

Similar to the first equation, this equation involves an absolute value. We'll also need to consider two cases.

Case 1: $x$ is positive ($x \geq 0$) In this case, $|x| = x$, so the equation becomes: $7x - 3(x + 2) = -10$ $7x - 3x - 6 = -10$ $4x = -4$ $x = -1$

Case 2: $x$ is negative ($x < 0$) In this case, $|x| = -x$, so the equation becomes: $7(-x) - 3(x + 2) = -10$ $-7x - 3x - 6 = -10$ $-10x = -4$ $x = \frac{2}{5}$

The solutions for Equation 2 are $x = -1$ and $x = \frac{2}{5}$.

So, the solutions for the given equations are: Equation 1: $x = 1$ and $x = \frac{1}{3}$ Equation 2: $x = -1$ and $x = \frac{2}{5}$.