Question

Sin3x*Cos 4x+cos 3x*Sin4x=3/2​

Answer 1

Ответ:

sin7x=3/2

Объяснение:

Answer 2

The given equation is:

$\sin(3x) \cdot \cos(4x) + \cos(3x) \cdot \sin(4x) = \frac{3}{2}$.

We can use the trigonometric identity $\sin(A + B) = \sin A \cdot \cos B + \cos A \cdot \sin B$ to simplify the left side of the equation:

$\sin(3x + 4x) = \sin(7x)$.

So the equation becomes:

$\sin(7x) = \frac{3}{2}$.

Now, the equation $\sin(7x) = \frac{3}{2}$ has no real solutions. The sine function ranges between -1 and 1, so it's not possible for $\sin(7x)$ to equal $\frac{3}{2}$ for any real value of $x$.

Therefore, the equation $\sin(3x) \cdot \cos(4x) + \cos(3x) \cdot \sin(4x) = \frac{3}{2}$ has no real solutions. It's possible that there might be a mistake or a misunderstanding in the given equation.