Question

1) x2 + 7x - 60 = 0;ааааааааааааааааааааааааааааааааа​

Answer 1

x²+7x-60=0;

D=7²-4*1*(-60)=49+240=289=17²;

x1=(-7-17)/2=-24/2=-12;

x2=(-7+17)/2=10/2=5;

Answer 2

To solve the quadratic equation $x^2 + 7x - 60 = 0$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a = 1$, $b = 7$, and $c = -60$. Now, plug these values into the formula:

$x = \frac{-7 \pm \sqrt{7^2 - 4(1)(-60)}}{2(1)}$

First, calculate the discriminant inside the square root:

$D = 7^2 - 4(1)(-60) = 49 + 240 = 289$

Now, substitute $D$ back into the formula:

$x = \frac{-7 \pm \sqrt{289}}{2(1)}$

Now, take the square root of 289:

$x = \frac{-7 \pm 17}{2}$

Now, you have two possible solutions, one with the positive square root and one with the negative square root:

1. $x = \frac{-7 + 17}{2} = \frac{10}{2} = 5$
2. $x = \frac{-7 - 17}{2} = \frac{-24}{2} = -12$

So, the solutions to the equation $x^2 + 7x - 60 = 0$ are $x = 5$ and $x = -12$.