Question

6arcsin(x²-6x+8.5)=P

Answer 1

Ответ:

x1=2

x2=4

Объяснение:

arcsin(x^2-6x+8,5)=П/6

x^2-6x+8,5=0,5

x^2-6x+8=0

x1=4

x2=2

Answer 2

To solve the equation $6\arcsin(x^2 - 6x + 8.5) = P$, we can start by isolating the $x^2 - 6x + 8.5$ term.

Divide both sides of the equation by 6:

$$\arcsin(x^2 - 6x + 8.5) = \frac{P}{6}$$

Now, we need to get rid of the arcsin function to isolate $x^2 - 6x + 8.5$. To do this, we can take the sine of both sides, which will cancel out the arcsin:

$$\sin\left(\arcsin(x^2 - 6x + 8.5)\right) = \sin\left(\frac{P}{6}\right)$$

The sine and arcsin functions are inverse functions, so they cancel each other out:

$$x^2 - 6x + 8.5 = \sin\left(\frac{P}{6}\right)$$

Now, you can solve for $x$:

$$x^2 - 6x + 8.5 = \sin\left(\frac{P}{6}\right)$$

This is a quadratic equation. You can rearrange it and set it to zero:

$$x^2 - 6x + 8.5 - \sin\left(\frac{P}{6}\right) = 0$$

You can use the quadratic formula to solve for $x$:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

In this case, $a = 1$, $b = -6$, $c = 8.5 - \sin\left(\frac{P}{6}\right)$. Plug these values into the quadratic formula and you'll have your solutions for $x$.