Question

Решите графическим методом систему уравнений и найдите координаты точки пересечения графиков функций {y-x=2 {y+x=10 Смотреть ответ Помогите пожалуйста у меня СОЧ ау Пеппер Пеппер Ответ: М (4; 6) Объяснение: {y-x=2      у=х+2;   х=0   у=2;   х=2   у=4 {y+x=10    у=10-х;  х=5   у=5;   х=6   у=4 Новые вопросы в Алгебра Розв'яжіть систему рівнянь способом додавання. { 5x+6y=215, 7x+3y=166; розв'яжіть систему рівнянь способом підстановки. { x-y=2, 3x-2y=9; 5. За умовою задачі складіть вираз зі змінними.Микола купив м ручок по 12 грн і 14 зошитів по л грн, заплативши за зошити більше, ніж за ручки. На скі … льки більше заплатив хлопчик за зошити, ніж за ручки? Обчисліть значення отриманого виразу при м=7, п=8.6. За умовою задачі складіть вираз зі змінною.Майстер щогодини виготовляв а деталей, а його учень на 7 деталей менше. Скільки деталей вони виготовили разом, якщо майстер працював 6 год, а учень- 4 год?​ Розв'яжіть систему рівнянь графічно { 5x+4y=8, -2x+3y=7; Розв'язком якого рівняння є пара чисел (2;1)? А) 4x-3y=8; Б)2x+3y=7; B) -3x-6y=9; Г) 7x+5y=10. Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Давайте решим данную систему уравнений графическим методом.

Сначала перепишем систему уравнений:

1. $y - x = 2$
2. $y + x = 10$

Для того чтобы найти точку пересечения графиков этих двух функций, давайте построим их графики на координатной плоскости.

Для первого уравнения ($y - x = 2$) выразим $y$ через $x$:

$y = x + 2$

Теперь для второго уравнения ($y + x = 10$) выразим $y$ через $x$:

$y = 10 - x$

Теперь мы имеем две функции, представленные в виде графиков: $y = x + 2$ и $y = 10 - x$.

Теперь построим эти два графика на координатной плоскости:

Для $y = x + 2$ мы можем выбрать несколько точек и построить график:

• Когда $x = 0$, $y = 0 + 2 = 2$, так что точка (0, 2) лежит на графике.
• Когда $x = 1$, $y = 1 + 2 = 3$, так что точка (1, 3) также лежит на графике.

Теперь для $y = 10 - x$:

• Когда $x = 0$, $y = 10 - 0 = 10$, так что точка (0, 10) лежит на графике.
• Когда $x = 1$, $y = 10 - 1 = 9$, так что точка (1, 9) также лежит на графике.

Теперь мы имеем два графика:

1. График функции $y = x + 2$, проходящий через точки (0, 2) и (1, 3).
2. График функции $y = 10 - x$, проходящий через точки (0, 10) и (1, 9).

Теперь найдем точку пересечения этих двух графиков. По графику видно, что они пересекаются в точке (4, 6).

Таким образом, решение системы уравнений:

1. $y - x = 2$
2. $y + x = 10$

есть точка пересечения графиков функций, которая равна (4, 6).