Question

А) (x+6) (x+5); б) (a-4) (a+1); в) (2-y) (y-8);г) (a-4) (2a+1);д) (2y-1) (3y+2);е) ( 5x-3) (4-3x).​

Answer 1

а)... = x²+5x+6x+30 = x²+11x+30.

б)... = a²+a-4a-4 = a²-3a-4.

в)... = 2y-16-y²+8y = 10y-16-y².

г)... = 2a²+a-8a-4 = 2a²-7a-4.

д)... = 6у²+4y-3y-2 = 6y²+y-2.

e)... = 20x-15x²-12+9x = 29x-15x²-12.

Answer 2

Давайте умножим указанные биномы:

А) (x+6) (x+5) = x^2 + 5x + 6x + 30 = x^2 + 11x + 30

Б) (a-4) (a+1) = a^2 + a - 4a - 4 = a^2 - 3a - 4

В) (2-y) (y-8) = 2y - 16 - y^2 + 8y = -y^2 + 10y - 16

Г) (a-4) (2a+1) = 2a^2 + a - 8a - 4 = 2a^2 - 7a - 4

Д) (2y-1) (3y+2) = 6y^2 + 4y - 3y - 2 = 6y^2 + y - 2

Е) (5x-3) (4-3x) = 20 - 15x - 12x + 9x^2 = 9x^2 - 27x + 20