Question

(3ab+2)(3ab-2)=(3ab)²-2²​

Answer 1

Ответ:

?? там же все уже решено нет разве

Answer 2

The expression you've provided is a multiplication of two binomials:

(3ab + 2)(3ab - 2)

To solve it, you can use the distributive property of multiplication (also known as FOIL, which stands for First, Outer, Inner, Last). Here's how you can expand this expression:

(3ab + 2)(3ab - 2)

First, multiply the "First" terms: (3ab)(3ab) = (3ab)^2 = 9a^2b^2

Next, multiply the "Outer" terms: (3ab)(-2) = -6ab

Then, multiply the "Inner" terms: (2)(3ab) = 6ab

Finally, multiply the "Last" terms: (2)(-2) = -4

Now, combine all these results:

(3ab + 2)(3ab - 2) = 9a^2b^2 - 6ab + 6ab - 4

Notice that the terms "-6ab" and "+6ab" cancel each other out:

9a^2b^2 - 6ab + 6ab - 4 = 9a^2b^2 - 4

So, the expanded form of the expression is:

9a^2b^2 - 4

This is not the same as (3ab)^2 - 2^2, which would be:

(3ab)^2 - 2^2 = 9a^2b^2 - 4

So, your original expression, (3ab + 2)(3ab - 2), is indeed equal to (3ab)^2 - 2^2.