Question

D(3d-1)^2-3d(2+d)^2=..

Answer 1

Ответ:

d×((3d-1)²-3(2+d))

d×(9d²-6d+1-3(4+4d+d²))

d×(9d²-6d+1-12-12d-3d²)

d×(6d²-6d+1-12-12²)⇒d*(6d²-18d+1-12)=D×(6d²-18d-11)

Объяснение:

Answer 2

Ответ:

Объяснение:

d(3d-1)²-3d(2+d)²= d(9d²-6d+1)-3d(4+4d+d²)=                                                                                                                  =9d³-6d²+d-12d-12d²-3d³=6d³-18d²-11d

Answer 3

To simplify the expression D(3d-1)^2 - 3d(2+d)^2, you can follow these steps:

1. Expand the squared terms:

   (3d-1)^2 = (3d-1)(3d-1) = 9d^2 - 6d + 1

   (2+d)^2 = (2+d)(2+d) = 4 + 4d + d^2

2. Now, substitute these expanded expressions back into the original equation:

   D(9d^2 - 6d + 1) - 3d(4 + 4d + d^2)

3. Distribute the constants D and -3d into their respective terms:

   9Dd^2 - 6Dd + D - 12d - 12d^2 - 3d^3

4. Combine like terms:

   9Dd^2 - 3d^3 - 6Dd - 12d^2 - 12d + D

So, the simplified expression is:

9Dd^2 - 3d^3 - 12d^2 - 6Dd - 12d + D