Question

(х²+1)² + (х²-х) = 1​

Answer 1

Ответ:

х=0

Объяснение:

(х²+1)²+(х²-х)=1

х⁴+2х²+х²-х=1-1

х⁴+3х²-х=0

х=0

Answer 2

Ответ:

х2 обчислювала за формулою: ах²+bx+c=0

Answer 3

To solve the equation (x² + 1)² + (x² - x) = 1, you can follow these steps:

1. Expand the expressions: (x² + 1)² = (x⁴ + 2x² + 1) (x² - x)

2. Rewrite the equation with the expanded expressions: (x⁴ + 2x² + 1) + (x² - x) = 1

3. Combine like terms: x⁴ + 2x² + 1 + x² - x = 1

4. Group like terms together: (x⁴ + 3x² - x) + 1 = 1

5. Subtract 1 from both sides of the equation to isolate the polynomial: x⁴ + 3x² - x = 0

Now, you have a quartic equation in terms of x. To solve it, you can try factoring, but quartic equations are generally more complex to solve by factoring. Another common approach is to use numerical methods or a graphing calculator to find approximate solutions.

Without additional information or constraints, finding the exact solutions for x may require more advanced mathematical techniques.