Question

Log0,7(4-7x)=log0,7(8x-11)

Answer 1

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Answer 2

To solve the equation log₀.₇(4 - 7x) = log₀.₇(8x - 11), you can use the properties of logarithms.

Since both sides of the equation have the same base (0.7), you can equate the arguments (what's inside the logarithms) and solve for x:

4 - 7x = 8x - 11

Now, let's isolate x by moving the terms involving x to one side of the equation and constants to the other side:

4 + 11 = 8x + 7x

15 = 15x

Now, divide both sides by 15 to solve for x:

x = 15 / 15

x = 1

So, the solution to the equation is x = 1.