Question

(5x+3)^2-(5x-4)(5x+4)=4​

Answer 1

25х^2+30х+9-(25х^-16)=4 - формулы сокращённого умножения
25х^2+30х+9-25х^2+16=4 - раскрываем скобки
30х+9+16=4 - сократили
30х+25=4 - сложили числа
30х= 4-25 - перенесли числа в другую сторону от «х»
30х= -21 - вычислили разность
Х= -7/10 или х=-0,7 - ответ

Answer 2

To solve the equation $(5x+3)^2 - (5x-4)(5x+4) = 4$, follow these steps:

1. Expand both sides of the equation:

$(5x+3)^2 - (5x-4)(5x+4) = 4$

Expanding the left side:

$(5x+3)(5x+3) - (5x-4)(5x+4) = 4$

Now, use the FOIL method (First, Outer, Inner, Last) to expand both products:

$(25x^2 + 30x + 9) - (25x^2 - 16) = 4$

2. Distribute the negative sign on the right side:

$25x^2 + 30x + 9 - 25x^2 + 16 = 4$

3. Simplify the equation by canceling out like terms:

The $25x^2$ terms on both sides cancel each other out:

$30x + 9 - 16 = 4$

4. Combine constants on the left side:

$30x - 7 = 4$

5. Now, isolate the variable $x$:

Add 7 to both sides:

$30x = 11$

6. Finally, divide by 30 to solve for $x$:

$x = \frac{11}{30}$

So, the solution to the equation $(5x+3)^2 - (5x-4)(5x+4) = 4$ is $x = \frac{11}{30}$.