Question

F(x) =4x^2-2, x0=-1​

Answer 1

Ответ:

f(×)=4×=x0

2-2=0

x0=-1=x€о

Answer 2

To find the derivative of the function $F(x) = 4x^2 - 2$ at the point $x_0 = -1$, you can use the power rule for differentiation. The power rule states that if you have a function of the form $f(x) = ax^n$, where $a$ and $n$ are constants, then its derivative $f'(x)$ is given by:

$f'(x) = nax^{(n-1)}$

In your case, $F(x) = 4x^2 - 2$, so $a = 4$ and $n = 2$. Now, let's find the derivative:

$F'(x) = 2 \cdot 4x^{2-1} = 8x$

Now that we have the derivative, we can find the value of the derivative at $x_0 = -1$:

$F'(-1) = 8 \cdot (-1) = -8$

So, the derivative of the function $F(x) = 4x^2 - 2$ at the point $x_0 = -1$ is $F'(-1) = -8$.