Question

(Х+3) (х+7) -( х+4)^2=0

Answer 1

Ответ на фото,обращайтесь.

Answer 2

Ответ: x= -2,5
Вроде так

Answer 3

To solve the equation $(x+3)(x+7) - (x+4)^2 = 0$, you can follow these steps:

1. Expand the expressions: $(x+3)(x+7) = x^2 + 10x + 21$ $(x+4)^2 = x^2 + 8x + 16$

2. Substitute these expressions back into the equation: $x^2 + 10x + 21 - (x^2 + 8x + 16) = 0$

3. Simplify the equation by combining like terms: $x^2 + 10x + 21 - x^2 - 8x - 16 = 0$

4. Simplify further: $(x^2 - x^2) + (10x - 8x) + (21 - 16) = 0$

5. Continue simplifying: $2x + 5 = 0$

6. Now, isolate the variable x by subtracting 5 from both sides: $2x = -5$

7. Finally, divide both sides by 2 to solve for x: $x = -5/2$

So, the solution to the equation is $x = -5/2$.