Question

1) x² + 5x – 14 = 0; ​

Answer 1

Объяснение:

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Answer 2

To solve the quadratic equation x² + 5x - 14 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation:

• a is the coefficient of the x² term, which is 1 in this case.
• b is the coefficient of the x term, which is 5 in this case.
• c is the constant term, which is -14 in this case.

Now, plug these values into the quadratic formula:

x = (-5 ± √(5² - 4 * 1 * (-14))) / (2 * 1)

x = (-5 ± √(25 + 56)) / 2

x = (-5 ± √81) / 2

x = (-5 ± 9) / 2

Now, you have two possible solutions:

1. x = (-5 + 9) / 2 = 4 / 2 = 2
2. x = (-5 - 9) / 2 = -14 / 2 = -7

So, the solutions to the quadratic equation x² + 5x - 14 = 0 are x = 2 and x = -7.