Question

27²-34*3+9=64x²-112x+49=​

Answer 1

Ответ:

636

65x

Объяснение:

27×27−34×3+9

64*64−112+49

Answer 2

To solve the given equation $27^2 - 34 \times 3 + 9 = 64x^2 - 112x + 49$, we'll first simplify the left-hand side and then equate it to the right-hand side to solve for $x$.

1. Simplify the left-hand side: $27^2 - 34 \times 3 + 9 = 729 - 102 + 9$ $= 636$

So, the equation becomes: $636 = 64x^2 - 112x + 49$

2. Move all terms to one side to set it equal to zero: $64x^2 - 112x + 49 - 636 = 0$ $64x^2 - 112x - 587 = 0$

3. Now, we'll solve the quadratic equation for $x$ using the quadratic formula: The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a$, $b$, and $c$ are the coefficients from the quadratic equation $ax^2 + bx + c = 0$.

In our case, $a = 64$, $b = -112$, and $c = -587$.

$x = \frac{-(-112) \pm \sqrt{(-112)^2 - 4 \times 64 \times -587}}{2 \times 64}$ $x = \frac{112 \pm \sqrt{12544 + 150016}}{128}$ $x = \frac{112 \pm \sqrt{162560}}{128}$ $x = \frac{112 \pm 403}{128}$

We have two possible solutions for $x$: $x_1 = \frac{112 + 403}{128} = \frac{515}{128}$

$x_2 = \frac{112 - 403}{128} = \frac{-291}{128}$

So, the solutions for the equation are: $x_1 = \frac{515}{128}$ and $x_2 = \frac{-291}{128}$.