Question

2a(a-b)+2b(a+b)?3p(8c+1)-8c(3p-5)?​

Answer 1

Ответ:

$2a(a - b) + 2b(a + b) = \\ 2 {a}^{2} - 2ab + 2ab + 2 {b}^{2} = 2 {a}^{2} + 2 {b}^{2}$

$3p(8c + 1) - 8c(3p - 5) = \\ 24pc + 3p - 24pc + 40c = \\ 3p + 40c$

Answer 2

It seems like you have two expressions, and you want to simplify them. Let's simplify each expression separately:

1. 2a(a - b) + 2b(a + b):

   Distribute the terms inside each parenthesis:

   = 2a^2 - 2ab + 2ab + 2b^2

   Notice that the "-2ab" and "+2ab" terms cancel each other out:

   = 2a^2 + 2b^2

2. 3p(8c + 1) - 8c(3p - 5):

   Distribute the terms inside each parenthesis:

   = 24pc + 3p - 24pc + 40c

   Notice that the "24pc" and "-24pc" terms cancel each other out:

   = 3p + 40c

So, the simplified expressions are:

1. 2a(a - b) + 2b(a + b) simplifies to 2a^2 + 2b^2.

2. 3p(8c + 1) - 8c(3p - 5) simplifies to 3p + 40c.