Question

12x-3•(7x+x)-(11-8)>4•(x-5)​

Answer 1

Ответ:

x<$1\frac{1}{16}$ или x∈(-∞,$1\frac{1}{16}$)

Объяснение:

$12x-3(7x+x)-(11-8)>4(x-5)\\12x-3*8x-3>4x-20\\12x-24x-3>4x-20\\-12x-3>20+3\\-16x>-17\\x$

Answer 2

To solve the inequality, let's simplify and isolate the variable "x" step by step:

1. Distribute the multiplication and subtraction inside the parentheses:

   12x - 3(7x + x) - (11 - 8) > 4(x - 5)

   12x - 3(8x) - 3 > 4x - 20

   12x - 24x - 3 > 4x - 20

   -12x - 3 > 4x - 20

2. Move the variable terms to one side and the constant terms to the other side of the inequality:

   -12x - 4x > -20 + 3

   -16x > -17

3. Divide both sides by -16 (note that since we are dividing by a negative number, we need to reverse the inequality):

   x < -17 / -16

   x < 1.0625

So, the solution to the inequality is x < 1.0625.