Question

Y= 2/3X - 3 і y= -2x +5 y= 1/2X +4 і y=2

Answer 1

Ответ:

1) 15/2; 2) 1,5; 3) 4,1.

Объяснение:

1) 2/3X-3=2

2/3X=2+3

2/3X=5

X=5÷2/3

X=15/2

2) -2X+5=2

-2X=2-5

-2X=-3

X=-3÷(-2)

X=1,5

3) 1/2X+4=2

1/2X=2-4

1/2X=-2

X=-2÷1/2

X=-4/1

Answer 2

It looks like you have a system of linear equations, and you'd like to find the solution (if any) to this system. The system consists of four equations:

1. $y = \frac{2}{3}x - 3$
2. $y = -2x + 5$
3. $y = \frac{1}{2}x + 4$
4. $y = 2$

To find the solution, you can set these equations equal to each other and solve for the values of $x$ and $y$ that satisfy all four equations:

1. $\frac{2}{3}x - 3 = -2x + 5$
2. $\frac{1}{2}x + 4 = 2$

Let's solve these equations step by step:

1. For the first equation, add $2x$ to both sides and add 3 to both sides: $\frac{2}{3}x + 2x = 5 + 3$ $\frac{8}{3}x = 8$

   Now, multiply both sides by $\frac{3}{8}$ to isolate $x$: $x = \frac{8}{3} \times \frac{3}{8}$ $x = 1$

   So, you've found that $x = 1$.

2. For the second equation, subtract 4 from both sides: $\frac{1}{2}x = 2 - 4$ $\frac{1}{2}x = -2$

   Now, multiply both sides by 2 to isolate $x$: $x = -2 \times 2$ $x = -4$

   So, you've found that $x = -4$.

Now that you have the values of $x$, you can use them to find $y$ by substituting them into any of the original equations. Let's use the first equation:

$y = \frac{2}{3}(1) - 3$ $y = \frac{2}{3} - 3$

To simplify this, you can express $\frac{2}{3}$ as a fraction with a common denominator:

$y = \frac{2}{3} - \frac{9}{3}$ $y = \frac{-7}{3}$

So, you've found that $y = \frac{-7}{3}$.

Therefore, the solution to the system of equations is $x = -4$ and $y = \frac{-7}{3}$.