Question

(4+a)^2= (2c-1)^2= (3b+2a)^2= (x^4-3)^2= (a+1)^3=

Answer 1

Ответ:1) а) = 16+8а+а^2

б) = 4х^2-4х+1

в) =4а^2+12ав+9в^2

г) = х^6-6х^3+9

2) а)=(х+3)^2=(х+3)(х+3)

б) = (5х-у)^2=(5х-у)(5х+у)

3) а) = 16х^2+24х+9-24х=16х^2+9

б) =18с^2-2(9с^2-6с+1)=18с^2-18с^2+12с-2=12с-2

Answer 2

Let's solve each of these equations one by one:

1. (4 + a)^2 = (2c - 1)^2

   To solve this equation, expand both sides:

   (4 + a)^2 = (16 + 8a + a^2) (2c - 1)^2 = (4c^2 - 4c + 1)

   Now, equate the two expressions:

   16 + 8a + a^2 = 4c^2 - 4c + 1

   Rearrange and simplify the equation:

   a^2 + 8a + 15 = 4c^2 - 4c

   Now, we have a relation between a and c.

2. (3b + 2a)^2 = (x^4 - 3)^2

   Expand both sides:

   (3b + 2a)^2 = 9b^2 + 12ab + 4a^2 (x^4 - 3)^2 = x^8 - 6x^4 + 9

   Equate the two expressions:

   9b^2 + 12ab + 4a^2 = x^8 - 6x^4 + 9

   Now, we have a relation between b and x.

3. (a + 1)^3

   There's no equation given for this expression; it's just a cubed expression.

If you have specific values for any of the variables (a, b, c, or x), you can use the equations to solve for the other variables. Otherwise, you have a set of relations that describe the relationships between these variables, but you would need more information to find specific values for them.