Question

(1/3x - y)(y+1/3x)алгебра​

Answer 1

$(\frac{1}{3} x - y)(y + \frac{1}{3} x) = (\frac{1}{3} x - y)(\frac{1}{3} x + y) = \frac{1}{9} {x}^{2} - {y}^{2}$

Answer 2

Ответ:

$(\frac{1}{3}x-y)(y+\frac{1}{3}x) =\frac{1}{9}x^{2} -y^{2}$

Answer 3

To multiply the expressions (1/3x - y) and (y + 1/3x), you can use the distributive property. Here's how you can do it step by step:

(1/3x - y)(y + 1/3x)

Step 1: Multiply the first terms of each expression: (1/3x) * (y) = (1/3xy)

Step 2: Multiply the first term of the first expression by the second term of the second expression: (1/3x) * (1/3x) = 1/9x^2

Step 3: Multiply the second term of the first expression by the first term of the second expression: (-y) * (y) = -y^2

Step 4: Multiply the second term of the first expression by the second term of the second expression: (-y) * (1/3x) = -y/3x

Now, combine all the terms you calculated in steps 1, 2, 3, and 4:

(1/3xy) + (1/9x^2) - y^2 - (y/3x)

So, the result of multiplying (1/3x - y) and (y + 1/3x) is:

(1/3xy) + (1/9x^2) - y^2 - (y/3x)