Question

Знайти проміжки зростання і спадання функції f(x)=2x²-3x²-12x​

Answer 1

Ответ:

зростання [-∞;-6]

спадання[-6;∞]

Объяснение:

f(x)=2x²-3x²-12x​

0=2х²-3х²-12х

2х²-3х²-12х=0

-х²-12х=0

-х(х-12)=0

х(х+12)=0

х1=-12

х2=0

Answer 2

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