Question

X-5/x+3+x+3/x-5 -2 1/2

Answer 1

Ответ:

Решение:4х^2-9х-4/2х

Answer 2

It seems like you're trying to simplify the expression $\frac{X - 5}{X + 3} + \frac{X + 3}{X - 5} - \frac{2}{1/2}$.

To simplify this expression, let's first deal with the fraction $\frac{2}{1/2}$. To divide by a fraction, you multiply by its reciprocal. The reciprocal of $1/2$ is $2$, so $\frac{2}{1/2} = 2 \times 2 = 4$.

Now, the expression becomes:

$$\frac{X - 5}{X + 3} + \frac{X + 3}{X - 5} - 4$$

To combine the fractions with different denominators, you need to find a common denominator. In this case, the common denominator is $(X + 3)(X - 5)$.

So, you need to rewrite the fractions with the common denominator:

$$\frac{(X - 5)^2}{(X + 3)(X - 5)} + \frac{(X + 3)^2}{(X + 3)(X - 5)} - 4 \times \frac{(X + 3)(X - 5)}{(X + 3)(X - 5)}$$

Now, the denominators are the same, so you can combine the fractions:

$$\frac{(X - 5)^2 + (X + 3)^2 - 4(X + 3)(X - 5)}{(X + 3)(X - 5)}$$

To simplify further, you can expand $(X - 5)^2$ and $(X + 3)^2$:

$$\frac{X^2 - 10X + 25 + X^2 + 6X + 9 - 4(X^2 - 2X - 15)}{(X + 3)(X - 5)}$$

Now, simplify the expression inside the numerator:

$$\frac{2X^2 - 4X + 64}{(X + 3)(X - 5)}$$

So, the simplified form of the given expression is:

$$\frac{2X^2 - 4X + 64}{(X + 3)(X - 5)}$$