Question

Log^1/3(5x-3)=log1/3(7x+5)

Answer 1

Ответ:

Раздели обе части на log1/3, получишь 5x-3=7x+5,

5x-7x=5+3,

-2x=8,

x= -4

Answer 2

To solve the equation $\log_{\frac{1}{3}}(5x - 3) = \log_{\frac{1}{3}}(7x + 5)$, you can use the properties of logarithms.

Since both logarithms have the same base ($\frac{1}{3}$), you can set the arguments (what's inside the logarithms) equal to each other:

$5x - 3 = 7x + 5$

Now, solve for (x:

Subtract $5x$ from both sides:

$-3 - 5 = 7x - 5x$

$-8 = 2x$

Now, divide both sides by 2:

$\frac{-8}{2} = \frac{2x}{2}$

$-4 = x$

So, $x = -4$ is the solution to the equation.