Question

(a-x)(a+x)-b(b+2)-(a-b-x)(a+b+x)=0

Answer 1

Ответ:

(a-x)(a+x)-b(b+2)-(a-b-x)(a+b+x)=0

a²-x²-b²-2b-a²+b²+x²=0

-2b=0

b=0

Answer 2

Ответ:

(a-x)(a+x)-b(b+2)-(a-b-x)(a+b+x)=0

а²-х²-b×(b+2) - (a-b-x)×(a+b+x)

a²-x²-b²-2b- (a-b-x)× (a+b+x)

a²-x²-b²-2b-( a²-(-b-x)²)

a²-x²-b²- 2b- (a²-( - ( b+x))²)

a²-x²-b²-2b- (a²-( b+x)²)

a²-x²- b²- 2b- a²+(b+x)²

-x²-b²- 2b+ (b+x)²

-x²-b²-2b+ b²+2bx+x²

-b²- 2b+b²+2bx

-2b+2bx

Ответ будеть: -2b+2bx

Answer 3

To solve the equation:

(a - x)(a + x) - b(b + 2) - (a - b - x)(a + b + x) = 0

Let's simplify it step by step:

1. Expand the terms:

(a^2 - x^2) - b(b + 2) - (a^2 - b^2 - x^2) = 0

2. Distribute the negative sign in the last term:

a^2 - x^2 - b(b + 2) - a^2 + b^2 + x^2 = 0

3. Cancel out the common terms (a^2 and x^2):

-b(b + 2) + b^2 = 0

4. Expand and simplify the left side:

-b^2 - 2b + b^2 = 0

5. The b^2 terms cancel out, leaving:

-2b = 0

6. Now, solve for 'b':

-2b = 0

Divide both sides by -2:

b = 0

So, the solution to the equation is b = 0.