Question

5(x-1)²+2(x+3)²=3(x+2)²​

Answer 1

Объяснение:

на фото есть ответ ....

удачи

Answer 2

To solve the equation 5(x-1)² + 2(x+3)² = 3(x+2)², you can follow these steps:

1. Expand and simplify both sides of the equation:

5(x-1)² + 2(x+3)² = 3(x+2)²

Expand the squared terms:

5(x² - 2x + 1) + 2(x² + 6x + 9) = 3(x² + 4x + 4)

Now distribute the constants:

5x² - 10x + 5 + 2x² + 12x + 18 = 3x² + 12x + 12

2. Combine like terms on both sides of the equation:

(5x² + 2x² - 3x²) + (-10x + 12x - 12) + (5 + 18) = 0

Now simplify each group of terms:

4x² - 3x - 12 + 23 = 0

3. Combine the constants:

4x² - 3x + 11 = 0

Now, you have a quadratic equation in standard form. You can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 4, b = -3, and c = 11. Plug these values into the formula:

x = (-(-3) ± √((-3)² - 4(4)(11))) / (2(4))

Simplify:

x = (3 ± √(9 - 176)) / 8

Since the discriminant (the value inside the square root) is negative, there are no real solutions. The solutions would be complex numbers. If you'd like to find the complex solutions, you can continue with the calculation:

x = (3 ± √(-167)) / 8

x = (3 ± i√167) / 8

So, the solutions are:

x = (3 + i√167) / 8 x = (3 - i√167) / 8

These are the complex solutions to the equation.