Question

X+2y-11=04X-5y+8=0 пжжжж​

Answer 1

Ответ:

(3;4)

Объяснение:

х=0-2у+11 (2)

4(0-2у+11)-5у+8=0 (1)

(1) 4(0-2у+11)-5у+8=0

-8у+44-5у+8=0

-8у-5у= -44-8

-13у= -52

у=52/13

у=4

(2) х=0-2у+11

Если у=4, то х= -2*4+11= -8+11=3

Answer 2

It seems like you've provided two equations, and it's possible that you want to solve for the values of 'x' and 'y' that satisfy both equations simultaneously. To do this, you can use the method of solving a system of linear equations.

Let's start by writing the two equations:

1. x + 2y - 11 = 0
2. 4x - 5y + 8 = 0

Now, you can solve this system of equations using either the substitution method or the elimination method. I'll use the elimination method in this example.

First, you can multiply the first equation by 4 and the second equation by 1 to make the coefficients of 'x' in both equations equal:

1. 4(x + 2y - 11) = 0
2. 1(4x - 5y + 8) = 0

This simplifies to:

1. 4x + 8y - 44 = 0
2. 4x - 5y + 8 = 0

Now, subtract the second equation from the first equation to eliminate 'x':

(4x + 8y - 44) - (4x - 5y + 8) = 0

This simplifies to:

13y - 52 = 0

Now, isolate 'y':

13y = 52

y = 52 / 13 y = 4

Now that you have the value of 'y', you can substitute it into either of the original equations to solve for 'x.' I'll use the first equation:

x + 2y - 11 = 0 x + 2(4) - 11 = 0 x + 8 - 11 = 0 x - 3 = 0

Now, isolate 'x':

x = 3

So, the solution to the system of equations is:

x = 3 y = 4