Question

1. Решите Уравнение 4х-3=3х+7 2. В треугольнике АВС угол А в 3 раза больше угла В, а угол С в 2 раза больше угла А. Вычислите величины углов треугольника АВС. 3. Решите систему уравнений А) {х-у=1 {х+у=3 Б) {2х-3у=3 {3х+2у=11 4. В двух коробках лежало 210 карандашей. Если в первой коробке число карандашей уменьшить вдвое, а во второй их число увеличить в 2 раза, то в двух коробках станет 240 карандашей. Сколько карандашей было в каждой коробке первоначально. Посмотреть ответы kupa94 kupa94 Ответ: 1. 4x-3x=7+3 x=10 3. A){2x=4 {x+y=3 . . {x=2 . {y=1 Объяснение: Остальное не знаю , прости,пожалуйста kiborg005003 kiborg005003 Ответ: Объяснение: Фото Новые вопросы в Алгебра На скільки значення виразу 27a3 + 4 – (9a2 – 3a + 1) (3a + 1) менше від числа 10? два муравья без остановочно ползают туда-сюда по линейке длиной 15 см скорость первого муравья 3 см в минуту А второго 5 см в минуту стартуют они с с … противоположных концов линейки Сколько раз встретятся муравьи за один час? вычислите интеграл. сверху 9 снизу 1 x-1 / корень из x( в числителе x-1, в знаменателе корень из x) Составьте числовое выражение и найдите его назначение №1. Для школи придбали 15 хокейних клю­чок і 5 м'ячів, заплативши за всю покупку 64 грн. Скільки коштує ключка і скільки коштує м'яч. коли відомо, що … 5 ключок дорожчі за 2 м'ячі на 3 грн? №2. За 4 години їзди автомобілем і 7 годин їзди поїздом туристи проїхали 640 км. Яка швидкість поїзда, якщо вона на 5 км/год більша від швидкості автомобіля? 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Answer 1

Конечно, давай разберем по порядку:

1. Уравнение $4x - 3 = 3x + 7$:

   Решение: $4x - 3x = 7 + 3$ $x = 10$

2. В треугольнике $ABC$ угол $A$ в 3 раза больше угла $B$, а угол $C$ в 2 раза больше угла $A$:

   Пусть угол $B$ равен $\alpha$. Тогда угол $A = 3\alpha$, а угол $C = 2 \cdot 3\alpha = 6\alpha$.

   Все углы треугольника в сумме равны $180^\circ$: $\alpha + 3\alpha + 6\alpha = 180$ $10\alpha = 180$ $\alpha = 18^\circ$

   Теперь можем найти все углы: $A = 3 \cdot 18 = 54^\circ$ $B = 18^\circ$ $C = 6 \cdot 18 = 108^\circ$

3. Система уравнений:

   А) $\begin{cases} x - y = 1 \\ x + y = 3 \end{cases}$

   Сложим оба уравнения: $2x = 4$ $x = 2$

   Подставим $x$ в первое уравнение: $2 - y = 1$ $y = 1$

   Таким образом, решение системы: $x = 2, y = 1$.

   Б) $\begin{cases} 2x - 3y = 3 \\ 3x + 2y = 11 \end{cases}$

   Умножим первое уравнение на 3, а второе на 2 и сложим их: $6x - 9y + 6x + 4y = 33$ $12x - 5y = 33$

   Решим уравнение $12x - 5y = 33$ с учетом $x = 2$ из предыдущего решения: $24 - 5y = 33$ $-5y = 9$ $y = -\frac{9}{5}$

   Таким образом, система не имеет решения.

4. Пусть в первой коробке было $x$ карандашей, а во второй $210 - x$. Условие задачи:

   $\frac{x}{2} + 2(210 - x) = 240$

   Решим уравнение: $\frac{x}{2} + 420 - 2x = 240$ $x + 840 - 4x = 480$ $3x = 360$ $x = 120$

   Таким образом, в первой коробке было 120 карандашей, а во второй $210 - 120 = 90$ карандашей.

Как-то так. Надеюсь, это поможет!